A mass of 10   kg is suspended vertically by a rope from the roof. When a horizontal force is applied…

A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is g=10 m s-2
  1. 100 N
  2. 200 N
  3. 140 N
  4. 70 N

Solution


Tcos⁡45°=mg

Tsin⁡45°=F

tan 45°=Fmg

F=mg=100 N

Asked in: JEE Main 2019 (09 Jan Shift 2)

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