
A mass ' $m$ ' moves with a velocity $v$ and collides inelastically with another identical mass. After…

- v
- $\sqrt{3} v$
- $2 v / \sqrt{3}$
- $v / \sqrt{3}$
Solution

$m v=m v_1 \cos \theta$ $0=\frac{m v}{\sqrt{3}}-m v_1 \sin \theta$ $\therefore v_1=\frac{2}{\sqrt{3}} v$
Asked in: JEE Main 2005
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