A marble block of mass $2 \mathrm{~kg}$ lying on ice when given a velocity of $6 \mathrm{~m} / \mathrm{s}$ is stopped by friction in $10 \mathrm{~s}$. Then the coefficient of friction is

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Aicharya · Accepted Answer

$a=\mu g=\frac{6}{10}$ [ using $\mathrm{v}=\mathrm{u}+\mathrm{at}$ ] $\Rightarrow \mu=\frac{6}{10 	imes g}=\frac{6}{10 	imes 10}=0.06$

A marble block of mass $2 \mathrm{~kg}$ lying on ice when given a velocity of $6 \mathrm{~m} / \mathrm{s}$…

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