A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are…

A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are ladies and 4 are men. Assume X and Y have no common friends. Then the total number of ways in which X and Y together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of X and Y are in this party is:
  1. 485
  2. 468
  3. 469
  4. 484

Solution

Here, m - men and L - ladies



Total=9×16+1+9×36+16

=144+1+324+16

=485

Asked in: JEE Main 2017 (02 Apr)

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