A man walks $4$ km/h for $2$ h then $5$ km/h for $1$ h. Total distance is

A man walks $4$ km/h for $2$ h then $5$ km/h for $1$ h. Total distance is
  1. $13$ km
  2. $9$ km
  3. $10$ km
  4. $15$ km

Solution

$4 \cdot 2 + 5 \cdot 1 = 13$.

Asked in: IMO

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