A man started from home at 14:30 hours and drove to a village, arriving there when the village clock…
A man started from home at 14:30 hours and drove to a village, arriving there when the village clock indicated 15:15 hours. After staying for 25 minutes, he drove back by a different route of length 1.25 times the first route at a rate twice as fast reaching home at 16:00 hours. As compared to the clock at home, the village clock is
10 minutes slow
5 minutes slow
10 minutes fast
5 minutes fast
Solution
Total elapsed by home clock = 16:00 - 14:30 = 90 minutes, minus 25 minutes stay = 65 minutes of travel. If onward time is 100 units, the return route is 1.25 times at twice the speed so return time = 125/2 = 62.5 units. Total 162.5 units = 65 minutes, so 100 units = 40 minutes. The man took 40 minutes to reach the village, so actual arrival time = 14:30 + 40 = 15:10. The village clock showed 15:15, so it is 5 minutes fast.