A $70 \mathrm{~kg}$ man leaps vertically into the air from a crouching position. To take the leap the man…

A $70 \mathrm{~kg}$ man leaps vertically into the air from a crouching position. To take the leap the man pushes the ground with a constant force $F$ to raise himself. The center of gravity rises by $0.5 \mathrm{~m}$ before he leaps. After the leap the c.g. rises by another $1 \mathrm{~m}$. The maximum power delivered by the muscles is : (Take $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )
  1. $6.26 \times 10^3$ Watts at the start
  2. $6.26 \times 10^3$ Watts at take off
  3. $6.26 \times 10^4$ Watts at the start
  4. $6.26 \times 10^4$ Watts at take off

Solution

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Asked in: JEE Main 2013 (23 Apr Online)

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