A man carrying a monkey on his shoulder does cycling smoothly on a circular track of radius $9 \mathrm{~m}$…

A man carrying a monkey on his shoulder does cycling smoothly on a circular track of radius $9 \mathrm{~m}$ and completes 120 resolutions in 3 minutes. The magnitude of centripetal acceleration of monkey is $\left(\right.$ in $\mathrm{m} / \mathrm{s}^2$ ) :
  1. $57600 \pi^2 \mathrm{~ms}^{-2}$
  2. Zero
  3. $4 \pi^2 \mathrm{~ms}^{-2}$
  4. $16 \pi^2 \mathrm{~ms}^{-2}$

Solution

$\begin{aligned} & \text { Given : } \mathrm{R}=9 \mathrm{~m}, \\ & 120 \text { revolution in } 3 \mathrm{~min} \\ & \omega=\frac{120 \mathrm{Rev} .}{3 \mathrm{~min} .}=\frac{120 \times 2 \pi \mathrm{rad}}{3 \times 60 \mathrm{sec}}=\frac{4 \pi}{3} \mathrm{rad} / \mathrm{s} \\ & \mathrm{a}_{\text {centripetal }}=\omega^2 \mathrm{R}=\left(\frac{4 \pi}{3}\right)^2 \times 9=16 \pi^2 \mathrm{~m} / \mathrm{s}^2\end{aligned}$

Asked in: JEE Main 2024 (05 Apr Shift 2)

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