A loop A B C D E F A of straight edges has six corner points A 0 , 0 , 0 , B 5 , 0 , 0 , C 5 , 5 , 0 , D 0 ,…

A loop ABCDEFA of straight edges has six corner points A0,0,0,B5,0,0,C5,5,0,D0,5,0,E0,5,5 and F0,0,5 . The magnetic field in this region is B=3i^+4k^T . The quantity of flux through the loop ABCDEFA (in Wb ) is _____________

Solution

ϕ=B.A=3i^+4k^.25i^+25k^

ϕ=2×25+4×25=175weber

Asked in: JEE Main 2020 (07 Jan Shift 1)

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