A long straight wire of radius a carries a steady current I . the current is uniformly distributed over its…

A long straight wire of radius a carries a steady current I . the current is uniformly distributed over its cross-section. The ratio of the magnetic fields B and B' , at radial distances a2 and 2a respectively, from the axis of the wire is:
  1. 14
  2. 12
  3. 1
  4. 4

Solution

Inside the wireBy amperes law
B.dl=μ0ienclosed
B.dlcos0=μ0Iπa2.πa22
Bdl=μ0I4
B2πa2=μ0I4
B=μ0I4πa
Outside the wire,
B=μ0I2πr=μ0I2π2a=μ0I4πa
So, BB=1.

Asked in: NEET 2016 (Phase 1)

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