A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A . The magnetic field at the…

A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is:
μ0=4π×10−7T m A−1
  1. 3.14×10–4 T
  2. 6.28×10–5 T
  3. 3.14×10–5 T
  4. 6.28×10–4 T

Solution

The magnetic field at the centre of the solenoid is given by, B=μ0ni

Where n is the number of turns per unit length
⇒B=4π×10-7×100(0.5)×2.5
⇒B=6.28×10-4 T

Asked in: NEET 2020 (Phase 1)

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