A logic circuit provides the output $Y$ as per the following truth table : $\begin{array}{|l|l|l|}\hline A &…
A logic circuit provides the output $Y$ as per the following truth table :
$\begin{array}{|l|l|l|}\hline A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 0 \\ \hline\end{array}$
The expression for the output $Y$ is :
$A \cdot \bar{B}+\bar{A}$
$\bar{B}$
$B$
$A \cdot B+\bar{A}$
Solution
$\begin{array}{|l|l|l|}\hline A & B & Y \\\hline 0 & 0 & 1 \\0 & 1 & 0 \\1 & 0 & 1 \\1 & 1 & 0 \\\hline \end{array}$
According to given truth table, output is independent on value of $A$
$\therefore$ Output $Y=\bar{B}$