A linear graph passes through $(0,0)$ and $(2,6)$. If $y$ depends linearly on $x$ through the origin, then…
A linear graph passes through $(0,0)$ and $(2,6)$. If $y$ depends linearly on $x$ through the origin, then for $x=5$ the value of $y$ is:
- $10$
- $12$
- $15$
- $18$
Solution
Slope $= 6/2 = 3$, so $y = 3x$. At $x=5$, $y=15$.
Asked in: IMO
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