A line drawn through the point P 4 , 7 cuts the circle x 2 + y 2 = 9 at the points A and B . Then P A ·…

1. $74$
2. $53$
3. $56$
4. $65$

Solution

      

As we know,

 $\begin{array}{l}PA.PB=P{T}^2=S_1^2\\ \\ S_1=\sqrt{16+49-9}=\sqrt{56}\\ \\ \Rightarrow S_1^2=56\\ \\ \Rightarrow PA.PB=56\end{array}$

Asked in: JEE Main 2017 (09 Apr Online)

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