A light wave has a frequency of \(4 \times 10^{14} \mathrm{~Hz}\) and a wavelength of \(5 \times 10^{-7}…

A light wave has a frequency of \(4 \times 10^{14} \mathrm{~Hz}\) and a wavelength of \(5 \times 10^{-7} \mathrm{~m}\) in a medium. The refractive index of the medium is
  1. 1.5
  2. 1.33
  3. 1.0
  4. 0.66

Solution

$ v = 4 \times 10^{14} \, \text{Hz} $ $ \lambda_m = 5 \times 10^{-7} \, \text{m} $ Frequency of light wave in air $\begin{aligned} \lambda_{\text{air}} & =\frac{\text{Velocity of light in air}}{\text{Frequency of light}}=\frac{3 \times 10^8}{4 \times 10^{14}} \\ & =7.5 \times 10^{-7} \, \text{m} \end{aligned}$ \(\therefore\) Refractive index of medium is given as \(\mu=\frac{\lambda_{\text {air }}}{\lambda_{\text {medium }}}=\frac{7.5 \times 10^{-7}}{5 \times 10^{-7}}=1.5\)

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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