A light unstretchable string passing over a smooth light pulley connects two blocks of masses $m_1$ and…

A light unstretchable string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$. If the acceleration of the system is $\frac{g}{8}$, then the ratio of the masses $\frac{m_2}{m_1}$ is :
  1. $8: 1$
  2. $5: 3$
  3. $4: 3$
  4. $9: 7$

Solution

$\begin{aligned} & a_{\text {sys }}=\left(\frac{m_2-m_1}{m_1+m_2}\right) g=\frac{g}{8} \\ & \Rightarrow \frac{m_2}{m_1}=\frac{9}{7}\end{aligned}$

Asked in: JEE Main 2024 (09 Apr Shift 1)

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