A light string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$ (vertically)…
A light string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$ (vertically). If the acceleration of the system is $\mathrm{g} / 8$, then the ratio of the masses is
8 : 1
9 : 7
4 : 3
5 : 3
Solution
$a=\frac{m_1-m_2}{m_1+m_2} g ; \frac{1}{8}=\frac{m_1-m_2}{m_1+m_2} \Rightarrow m_1: m_2=9: 7$