A light ray falls on a glass surface of refractive index 3 , at an angle 60 ° . The angle between the refracted and reflected rays would be:

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Aicharya · Accepted Answer

From Snell's law, μ 1 sin i = μ 2 sin r ⇒ 1 × sin 60 ° = 3 sin r ⇒ r = 30 ° Angle between the refracted say and reflected say is θ = 180 ° - i + r = 90 °

A light ray falls on a glass surface of refractive index 3 , at an angle 60 ° . The angle between the…

Solution