A light of wavelength ${ }^{\prime} \lambda_{1}{ }^{\prime}$ and velocity $\mathrm{C}_{1}$ travels from the…
A light of wavelength ${ }^{\prime} \lambda_{1}{ }^{\prime}$ and velocity $\mathrm{C}_{1}$ travels from the first medium of
refractive index ' $\mu_{1}$ ' into the second medium of refractive index ' $\mu_{2}$ '. The
wavelength and velocity of light in the second medium is $^{\prime} \lambda_{2}^{\prime}$ and $\mathrm{C}_{2}$ respectively.
The refractive index of second medium with respect to first medium is given by
$\frac{c_{2}}{c_{1}}$
$\frac{\mu_{2}}{\mu_{1}}$
$\frac{\mu_{1}}{\mu_{2}}$
$\frac{\lambda_{2}}{\lambda_{1}}$
Solution
Refractive Index:
- The refractive index of a transparent material is defined as the ratio of the speed of light in the vacuum to that of a medium.
$\mathrm{n}_{\mathrm{m}}=\frac{c}{v}$ where,
$\mathrm{c}=$ speed of light in vacuum.
$v=$ speed of light in the medium.
- Refractive index of transparent medium denoted by $\mathbf{n}_{\mathrm{m}}$ -
- The Refractive index of water is $\mathbf{1 0 . 3 3}$ means that light travels $\mathbf{1 . 3 3}$ times fast than in water.
- An optically denser medium may not possess greater mass density.
- The refractive index of one medium to that of another medium is given by.
$\frac{n_1}{n_2}=\frac{v_2}{v_1}$
Where,
$\mathrm{n}_1=$ refractive index of medium -1
$\mathrm{n}_2=$ refractive index of medium -2
$v_2=$ velocity of light in the second medium.
$v_1=$ velocity of light in the first medium.