A light from Paschen series of hydrogen atom is able to eject photoelectrons from a metal. Then the work…
- $3: 4 \mathrm{eV}$
- $1.54 \mathrm{eV}$
- None of these
- $1.1 \mathrm{eV}$
Solution

So photons of paschen series have energies, ranging from $E_{\min }=E_{n=4}-E_{n=3}$ $\begin{aligned} & =-0.85-(-1.5 \mathrm{l}) \\ & =0.66 \mathrm{eV}\end{aligned}$ to $E_{\max }=E_{n=\infty}-E_{n=3}$ $\begin{aligned} & =0-(-1.5 \mathrm{l}) \\ & =1.51 \mathrm{eV}\end{aligned}$ So, if a photon of paschen series able to emit a photoelectron from a metal, then work function $\phi_0$ of metal must be such that, $\phi_0 \leq$ Photon energy or $\phi_0 \leq 1.51 \mathrm{eV}$ Only matching option is options (d).
Asked in: AP EAMCET 2022 (07 Jul Shift 1)