A large tank filled with water to a height ' $h$ ' is to be emptied through a small hole at the bottom. The ratio of the time taken for the level to fall from ' $h$ ' to $\frac{'}{2}$ ' and that taken for the level to fall from $\frac{1 h}{2}$ to ' 0 ' is

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Aicharya · Accepted Answer

The time to emply the tank, $\begin{aligned} & t=\sqrt{\frac{2 h}{g}} \Rightarrow t \propto \sqrt{h} \\ & \therefore \frac{t_1}{t_2} \\ &=\frac{\sqrt{h}-\sqrt{\frac{h}{2}}}{\sqrt{\frac{h}{2}}-\sqrt{0}}=(\sqrt{2}-1) \end{aligned}$

A large tank filled with water to a height ' $h$ ' is to be emptied through a small hole at the bottom. The…

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