A large square container with thin transparent vertical walls and filled with water refractive index 4 3 is kept on a horizontal table. A student holds a thin straight wire vertically inside the water 12 cm from one of its corners, as shown schematically in the figure. Looking at the wire from…

Question

A large square container with thin transparent vertical walls and filled with water $(refractive index \frac{4}{3})$ is kept on a horizontal table. A student holds a thin straight wire vertically inside the water $12 cm$ from one of its corners, as shown schematically in the figure. Looking at the wire from this corner, another student sees two images of the wire, located symmetrically on each side of the line of sight as shown. The separation (in $cm$ ) between these images is ________.

Aicharya · Accepted Answer

$P_1 O = \frac{12}{\sqrt{2}} \, 	ext{cm}$ $P_1 I_1 = \frac{12}{\sqrt{2} 	imes \frac{4}{3}} = \frac{9}{\sqrt{2}} \, 	ext{cm}$ $O I_1 = \frac{12}{\sqrt{2}} - \frac{9}{\sqrt{2}} = \frac{3}{\sqrt{2}}; \, O I_2 = \frac{3}{\sqrt{2}} \, 	ext{cm}$ $I_1 I_2 = \frac{3}{\sqrt{2}} 	imes \frac{1}{\sqrt{2}} 	imes 2 = 3$ The above solution is assumed according to the normal incidence. If we consider the actual angle of incidence, i.e., $45^{\circ}$ the answer comes to be $3$.

A large square container with thin transparent vertical walls and filled with water refractive index 4 3 is…

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