A laboratory mixture of $200\text{ g}$ contains dry sand and iron filings. If $40\%$ of the total mass of…

A laboratory mixture of $200\text{ g}$ contains dry sand and iron filings. If $40\%$ of the total mass of the mixture is iron filings, what mass of sand remains after all the iron filings are completely extracted using a strong magnet?
  1. $80\text{ g}$
  2. $120\text{ g}$
  3. $140\text{ g}$
  4. $160\text{ g}$

Solution

The mass of iron filings is $40\%$ of $200\text{ g} = 80\text{ g}$. Subtracting this from the total gives $200\text{ g} - 80\text{ g} = 120\text{ g}$ of remaining sand.

Asked in: Homi Bhabha Practice

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