A kite has diagonals of length $24$ cm and $18$ cm. Find its area.
A kite has diagonals of length $24$ cm and $18$ cm. Find its area.
- $432 \text{ cm}^{2}$
- $216 \text{ cm}^{2}$
- $108 \text{ cm}^{2}$
- $84 \text{ cm}^{2}$
Solution
For a kite, area $= \dfrac{1}{2}\times d_{1}\times d_{2} = \dfrac{1}{2}\times 24 \times 18 = 216 \text{ cm}^{2}$.
Asked in: IMO
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