A kind of bacteria grows by $t^3$ in $t \mathrm{~s}$. Time taken for the rate of growth of the bacteria to become 1200 per $s$ is

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Aicharya · Accepted Answer

Given, $\frac{d N}{d t}=t^3,$ When, rate of growth is 1200 we have, $\begin{aligned} & \frac{d}{d t}\left(\frac{d N}{d t}\right)=1200 \Rightarrow \frac{d}{d t} t^3=1200 \ & \Rightarrow \quad 3 t^2=1200 \Rightarrow t^2=400 \ & \Rightarrow \quad t=20 \mathrm{sec} \ \end{aligned}$

A kind of bacteria grows by \(t^3\) in \(t \mathrm{~s}\). Time taken for the rate of growth of the bacteria…

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