A is twice the age of B. After $5$ years, A will be $\dfrac{3}{2}$ times B's age. Present age of B is

A is twice the age of B. After $5$ years, A will be $\dfrac{3}{2}$ times B's age. Present age of B is
  1. $5$
  2. $10$
  3. $15$
  4. $20$

Solution

$2x + 5 = \dfrac{3}{2}(x + 5) \Rightarrow 4x + 10 = 3x + 15 \Rightarrow x = 5$.

Asked in: IMO

Practice more LINEAR EQUATIONS IN ONE VARIABLE questions on Aicharya