A is twice as old as B; their ages sum to $33$. Age of A is

A is twice as old as B; their ages sum to $33$. Age of A is
  1. $22$
  2. $11$
  3. $33$
  4. $15$

Solution

B $= x$, A $= 2x$. $3x = 33 \Rightarrow x = 11$. A $= 22$.

Asked in: IMO

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