A $70 \mathrm{mH}$ inductor is connected to $220 \mathrm{~V}, 50 \mathrm{~Hz} \mathrm{AC}$ supply. The rms…
A $70 \mathrm{mH}$ inductor is connected to $220 \mathrm{~V}, 50 \mathrm{~Hz} \mathrm{AC}$ supply. The rms value of the current in the circuit is
- $\frac{100}{\sqrt{2} \pi} \mathrm{A}$
- $10 \mathrm{~A}$
- $\frac{50}{\pi} \mathrm{A}$
- $\frac{10 \sqrt{2}}{\pi} \mathrm{A}$
Solution
As $i_{\mathrm{rms}}=\frac{\mathrm{V}_{\mathrm{rms}}}{\chi_{\mathrm{L}}}=\frac{\mathrm{V}_{\mathrm{rms}}}{\omega \mathrm{L}}=\frac{220}{2 \pi \times 50 \times 70 \times 10^{-3}}=10 \mathrm{~A}$
Asked in: AP EAMCET 2022 (05 Jul Shift 2)
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