A hydrogen gas electrode is made by dipping platinum wire in a solution of $\mathrm{HCl}$ of…

A hydrogen gas electrode is made by dipping platinum wire in a solution of $\mathrm{HCl}$ of $\mathrm{pH}=10$ and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be ?
  1. $0.59 \mathrm{~V}$
  2. $0.118 \mathrm{~V}$
  3. $1.18 \mathrm{~V}$
  4. $0.059 \mathrm{~V}$

Solution

$\mathrm{H}_{2} \longrightarrow 2 \mathrm{H}^{+}+2 \mathrm{e}^{-}$
$1 \mathrm{~atm} \quad 10^{-10}$
$\mathrm{E}_{\mathrm{H}_{2} / \mathrm{H}^{+}}=0-\frac{0.059}{2} \log \frac{\left(10^{-10}ight)^{2}}{1}$
$\mathrm{E}_{\mathrm{H}_{2} / \mathrm{H}^{+}}=+0.59 \mathrm{~V}$ .

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more ELECTROCHEMISTRY questions on Aicharya