A hydrogen atom in its ground state absorbs 10 . 2 eV of energy. The angular momentum of electron of the…

A hydrogen atom in its ground state absorbs 10.2eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of (Given, Planck's constant =6.6×10-34Js).
  1. 2.10×10-34Js
  2. 1.05×10-34Js
  3. 3.15×10-34Js
  4. 4.2×10-34Js

Solution

Energy absorbed is given by,

ΔE=13.6×1n12-1n22

10.2=13.6×1n12-1n22

Therefore, we get, n1=1 & n2=2

The change in angular momentum

ΔL=n2h2π-n1h2π=h2π

=1.05×10-34 J s

Asked in: JEE Main 2022 (27 Jun Shift 1)

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