A hydrocarbon with formula C8H18 gives only one monochloro derivative. The hydrocarbon is

A hydrocarbon with formula C8H18 gives only one monochloro derivative. The hydrocarbon is
  1. n-octane
  2. 2-methylheptane
  3. $2,2,4$ -trimethy pentane
  4. 2, $2,3,3$ -tetramethyl butane.

Solution

$\mathrm{C}_{8} \mathrm{H}_{18} \stackrel{\mathrm{Cl}_{2}}{ightarrow}$ one monochlorintaion product.
Compound in which all hydrogen atoms are equivalent will form one monochloro derivative. From, the given reaction we can say that this $2,2,3,3$ tetramethyl butane give only one chlorination product as chlorine is added to one of the $-\mathrm{CH}_{3}$ group.
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Asked in: JEE-TOPICTESTS-CHEMISTRY

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