A horizontal ray of light is incident on the right-angled prism with prism angle $6^{\circ}$. If the…
- $4^{\circ}$
- $6^{\circ}$
- $9^{\circ}$
- $10^{\circ}$
Solution
Deviation produced by a thin prism $\delta=(\mu-1) A=\left(\frac{3}{2}-1\right) 6^{\circ}=3^{\circ}$ $\begin{aligned} \text { Angle of emergence }=e & =6^{\circ}+3^{\circ} \\ & =9^{\circ}\end{aligned}$
Asked in: NEET 2023 (Manipur)