A heavy box of mass $50 \mathrm{~kg}$ is moving on a horizontal surface. If co-efficient of kinetic friction…

A heavy box of mass $50 \mathrm{~kg}$ is moving on a horizontal surface. If co-efficient of kinetic friction between the box and horizontal surface is 0.3 then force of kinetic friction is :
  1. $1.47 \mathrm{~N}$
  2. $147 \mathrm{~N}$
  3. $14.7 \mathrm{~N}$
  4. $1470 \mathrm{~N}$

Solution


$F_k=\mu_k N=0.3 \times 50 \times 9.8=147 N$

Asked in: JEE Main 2024 (05 Apr Shift 2)

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