A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated…
A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be
-
doubled
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four times
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one fourth
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halved
Solution
$\mathrm{H}=\frac{\mathrm{V}^2 \Delta \mathrm{t}}{\mathrm{R}}$
$\mathrm{H}^{\prime}=\frac{\mathrm{V}^2}{\mathrm{R}^{\prime}} \Delta \mathrm{t} \quad$ Given $\mathrm{R}^{\prime}=\mathrm{R} / 2$
Asked in: JEE Main 2005
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