A heat engine absorbs heat Q 1 at temperature T 2 and heat Q 2 at temperature T 2 . Work done by the engine is (Q 1 +Q 2 ) . This data:

Question

Aicharya · Accepted Answer

According to the first law of thermodynamics:
$∆ U = Q + W - - - - - - (1)$
Change in internal energy $∆ U = 0$ , for heat engines, because initial and final states are same. Internal energy is a state function.
From equation ( $1$ ),
$0 = Q + W$
$W = - Q$
Total work done $=$ $-$ Total heat exchanged
Total work done $= - (Q_{1} + Q_{2})$
Work done by heat engine is $Q_{1} + Q_{2}$

A heat engine absorbs heat Q 1 at temperature T 2 and heat Q 2 at temperature T 2 . Work done by the engine…

Solution