A has some coins. He gives half of the coins and 2 more to B. B gives half of the coins and 2 more to C. C gives half of the coins and 2 more to D. The number of coins D has now, is the smallest two-digit number. How many coins does A have in the beginning?

Question

Aicharya · Accepted Answer

D has the smallest two-digit number = 10. Working backwards: D = C/2 + 2, so C/2 = 8 and C = 16. C = B/2 + 2, so B/2 = 14 and B = 28. B = A/2 + 2, so A/2 = 26 and A = 52.

A has some coins. He gives half of the coins and 2 more to B. B gives half of the coins and 2 more to C. C…

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