A graph of magnetic flux $\phi$ versus current (I) is shown for four inductors $\mathrm{A}, \mathrm{B}$, C,…

A graph of magnetic flux $\phi$ versus current (I) is shown for four inductors $\mathrm{A}, \mathrm{B}$, C, D. Smaller value of self inductance is for inductor
  1. A
  2. C
  3. B
  4. D

Solution

We have $\phi=\mathrm{LI} \quad$ or $\quad \mathrm{L}=\frac{\phi}{\mathrm{I}}$ self-inductance is given by the slope of the graph. Slope of line $A$ is maximum, hence it gives maximum value of self inductance.

Asked in: MHT CET 2020 (13 Oct Shift 2)

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