A glass cube of length $24 \mathrm{~cm}$ has a small air bubble trapped inside. When viewed normally from…
A glass cube of length $24 \mathrm{~cm}$ has a small air bubble trapped inside. When viewed normally from one face it is $10 \mathrm{~cm}$ below the surface. When viewed normally from the opposite face, its apparent distance is $6 \mathrm{~cm}$. The refractive index of glass is
1.50
1.40
1.45
1.55
Solution
Let $\mathrm{x}$ be the real depth from first surface
$10=\frac{\mathrm{x}}{\mu}$
When viewed from opposite face
$6=\frac{24-x}{\mu}$
By solving, $\mu=1.5$