A gaseous mixture was prepared by taking equal moles of $\mathrm{CO}$ and $\mathrm{N}_2$. If the total…

A gaseous mixture was prepared by taking equal moles of $\mathrm{CO}$ and $\mathrm{N}_2$. If the total pressure of the mixture was found 1 atmosphere, the partial pressure of the nitrogen $\left(\mathrm{N}_2\right)$ in the mixture is
  1. $0.8 \mathrm{~atm}$
  2. $0.9 \mathrm{~atm}$
  3. $1 \mathrm{~atm}$
  4. $0.5 \mathrm{~atm}$

Solution

$\begin{array}{l} & \because { }^n \mathrm{CO} ={ }^n \mathrm{~N}_2 \\ & \therefore p_{\mathrm{CO}} =p_{\mathrm{N}_2} \\ & \text {Given, } p_{\mathrm{CO}}+p_{\mathrm{N}_2} =1 \mathrm{~atm} \\ & \text {or } 2 p_{\mathrm{N}_2} =1 \mathrm{~atm} \\ & \text {or } p_{\mathrm{N}_2} =0.5 \mathrm{~atm} \end{array}$

Asked in: NEET 2011 (Screening)

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