A gaseous mixture contains oxygen and nitrogen in the ratio of $1: 4$ by weight. Therefore, the ratio of…
- $1: 4$
- $1: 8$
- $7: 32$
- $3: 16$
Solution
The weight of nitrogen $=4 x$
Number of molecules of oxygen $=\frac{x}{32} \times N_{0}$
Number of molecules of nitrogen $=\frac{4 x}{28} \times N_{0}$
$\frac{\text { number of molecules of oxygen }}{\text { number of molecules of nitrogen }}=\frac{x \times 28}{32 \times 4 x} \quad=\frac{7}{32}$ ,
Asked in: JEE-TOPICTESTS-CHEMISTRY
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