A gas occupies $11.2 \mathrm{dm}^3$ at 105 kPa What is the volume if pressure is increased to 210 kPa ?

A gas occupies $11.2 \mathrm{dm}^3$ at 105 kPa What is the volume if pressure is increased to 210 kPa ?
  1. $5.6 \mathrm{dm}^3$
  2. $16.8 \mathrm{dm}^3$
  3. $22.4 \mathrm{dm}^3$
  4. $33.6 \mathrm{dm}^3$

Solution

According to Boyle's law, $\begin{aligned} & \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\ \therefore \quad & \mathrm{~V}_2=\frac{\mathrm{P}_1 \mathrm{~V}_1}{\mathrm{P}_2}=\frac{105 \mathrm{kPa} \times 11.2 \mathrm{dm}^3}{210 \mathrm{kPa}}=5.6 \mathrm{dm}^3 \end{aligned}$

Asked in: MHT CET 2024 (10 May Shift 1)

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