A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure P i = 10 5   P a   a n d   v o l u m e   V i = 10 - 3   m 3 changes to a final state at P f = 1 32 × 10 5   P a   a n d   V f = 8 × 10 -…

Question

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure P i = 10 5 &#160; P a &#160; a n d &#160; v o l u m e &#160; V i = 10 - 3 &#160; m 3 changes to a final state at P f = 1 32 &#215; 10 5 &#160; P a &#160; a n d &#160; V f = 8 &#215; 10 - 3 &#160; m 3 in an adiabatic quasi - static process, such that P 3 V 5 = constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at P i followed by an isochoric (isovolumetric) process at volumes V f . The amount of heat supplied to the system in the two step process is approximately

Aicharya · Accepted Answer

In adiabatic process P 3 V 5 = constant ⇒ P V 5 3 = constant ⇒ γ = 5 3 ⇒ C V = 3 2 R a n d C P = 5 2 R In another process ∆ Q = n C P ∆ T + n C v ∆ T = 5 2 n R T B - T A + 3 2 n R T C - T B ∆ Q = 5 2 P B V B - P A V A + 3 2 P C V C - P B V B Putting values ∆ Q = 587.5 J ≈ 588 J

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at…

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