A gas ' $X$ ' is dissolved in water at 2 bar pressure. Its mole fraction is 0.02 in solution. The mole…

A gas ' $X$ ' is dissolved in water at 2 bar pressure. Its mole fraction is 0.02 in solution. The mole fraction of water when the pressure of gas is doubled at the same temperature is
  1. $0.04$
  2. $0.98$
  3. $0.96$
  4. $0.02$

Solution

From Henry's law, if we increase the pressure then the mole fraction of gas in the water will increase by the same multiple. Hence, mole fraction of gas $=0.04$. Mole fraction of water $=0.96$

Asked in: AP EAMCET 2015

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