A gas $X$ is dissolved in water at 2 bar pressure. Its mole fraction in the solution is 0.02 . Find the mole…

A gas $X$ is dissolved in water at 2 bar pressure. Its mole fraction in the solution is 0.02 . Find the mole fraction of water in the solution when the pressure of the gas is doubled at the same temperature.
  1. 0.04
  2. 0.98
  3. 0.96
  4. 0.02

Solution

Pressure, $p=2$ bar Mole fraction, $ \begin{aligned} & \chi=0.02 \\ & p=K_{\mathrm{H}} \times \chi (Henry law)\\ & 2=K_{\mathrm{H}} \times 0.02...(i) \end{aligned} $ Pressure doubled. $ \begin{aligned} & p=K_{\mathrm{H}} \times \chi \\ & 4=K_{\mathrm{H}} \times \chi...(ii) \end{aligned} $ From Eqs. (i) and (ii) $ \frac{1}{2}=\frac{0.02}{\chi} \Rightarrow \chi=0.04 $

Asked in: AP EAMCET 2021 (24 Aug Shift 1)

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