A gas is compressed from a volume of \(2 \mathrm{~m}^3\) to a volume of \(1 \mathrm{~m}^3\) at a constant…

A gas is compressed from a volume of \(2 \mathrm{~m}^3\) to a volume of \(1 \mathrm{~m}^3\) at a constant pressure of \(100 \mathrm{Nm}^{-2}\). Then it is heated at constant volume by supplying \(150 \mathrm{~J}\) of energy. As a result, the internal energy of the gas
  1. increase by \(250 \mathrm{~J}\)
  2. decrease by \(250 \mathrm{~J}\)
  3. decrease by \(50 \mathrm{~J}\)
  4. increase by \(50 \mathrm{~J}\)

Solution

Since, gas is compressed from \(2 \mathrm{~m}^3\) to \(\mathrm{lm}^3\). Hence, work done on the gas is negative. \(W=-p \Delta V=-100(2-1)=-100 \mathrm{~J}\) Since, heat supplied, \(Q=150 \mathrm{~J}\) Hence, according to first law of thermodynamics, \(\begin{aligned} Q & =W+\Delta U \\ \Rightarrow \quad 150 & =-100+\Delta U \\ \Delta U & =150+100=250 \mathrm{~J} \end{aligned}\)

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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