A gas having $\gamma=\frac{5}{2}$ and volume 360 c.c. is suddenly compressed to 90 c.c. If the initial…
- $\frac{\mathbf{P}}{4}$
- 8 P
- 16 P
- 32 P
Solution
The problem describes an adiabatic compression process, governed by the relation $PV^\gamma = \text{constant}$, where $\gamma = \frac{5}{2}$.
Given initial pressure $P_1 = P$, initial volume $V_1 = 360\text{ c.c.}$, and final volume $V_2 = 90\text{ c.c.}$, the adiabatic relation yields $P_1 V_1^\gamma = P_2 V_2^\gamma$.
Solving for final pressure, $P_2 = P_1 \left(\frac{V_1}{V_2}\right)^\gamma = P \left(\frac{360}{90}\right)^{5/2}$.
Since $\frac{360}{90} = 4$, and $4^{5/2} = (4^{1/2})^5 = 2^5 = 32$, it follows that $P_2 = 32P$.
This matches option D.
Final answer: $\boxed{\text{D}}$
Asked in: MHT CET 2025 (05 May Shift 2)