A gas expands from a volume of $1 \mathrm{~m}^{3}$ to a volume of $2 \mathrm{~m}^{3}$ against an external…

A gas expands from a volume of $1 \mathrm{~m}^{3}$ to a volume of $2 \mathrm{~m}^{3}$ against an external pressure of $10^{5} \mathrm{Nm}^{-2}$. The work done by the gas will be
  1. $10^{2} \mathrm{~kJ}$
  2. $10^{2} \mathrm{~J}$
  3. $10^{3} \mathrm{~J}$
  4. $10^{5} \mathrm{~kJ}$

Solution

$\mathrm{W}=\mathrm{p} \Delta \mathrm{V}$ $=10^{5}(2-1)=10^{5} \mathrm{~J}=10^{2} \mathrm{~kJ}$

Asked in: TEST SERIES MHT-CET Full Test 6

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