A gas at N.T.P. is suddenly compressed to $\left(\frac{1}{4}\right)^{\mathrm{th}}$ of its original volume.…

A gas at N.T.P. is suddenly compressed to $\left(\frac{1}{4}\right)^{\mathrm{th}}$ of its original volume. The final pressure in (Given $\gamma=$ ratio of sp. heats $=\frac{3}{2}$ ) atmosphere is ( $\mathrm{P}=$ original pressure $)$
  1. $4\ P$
  2. $\frac {3}{2}\ P$
  3. $8\ P$
  4. $\frac {1}{4}\ P$

Solution

In Adiabatic compression, $\mathrm{PV}^\psi=$ constant Given $\mathrm{V}_{\text {new }}=\frac{1}{4} \mathrm{~V}$ and $\gamma=\frac{3}{2}$ $\begin{aligned} & \therefore \quad \frac{\mathrm{P}_{\mathrm{new}}}{\mathrm{P}}=\left(\frac{\mathrm{V}}{\mathrm{V}_{\text {new }}}\right)^7=\left(\frac{\mathrm{V}}{\frac{1}{4} \mathrm{~V}}\right)^{3 / 2} \\ & \therefore \quad \mathrm{P}_{\mathrm{new}}=8 \mathrm{P} \end{aligned}$

Asked in: MHT CET 2023 (09 May Shift 1)

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