A gas at $37^{\circ} \mathrm{C}$ is compressed adiabatically to half of its volume, then the final…

A gas at $37^{\circ} \mathrm{C}$ is compressed adiabatically to half of its volume, then the final temperature of the gas is (Ratio of specific heat capacities of the gas is 1.5)
  1. $165.3^{\circ} \mathrm{C}$
  2. $438.3^{\circ} \mathrm{C}$
  3. $400^{\circ} \mathrm{C}$
  4. $0^{\circ} \mathrm{C}$

Solution

In an Adiabatic process, $T V^{\gamma-1}=$ constant $ \Rightarrow T_1 \cdot V_1^{\gamma-1}=T_2 V_2^{\gamma-1} \Rightarrow T_2=T_1\left(\frac{V_1}{V_2}\right)^{\gamma-1} $ Here, $r=1.5, V_2=V_1 / 2$ and $T_1=37^{\circ} \mathrm{C}=310.15 \mathrm{~K}$ So, final temperature is $T_2=15 \times(2)$ $ \begin{aligned} & =310.15 \times \sqrt{2} \\ & =437.31 \mathrm{~K}=164.12^{\circ} \mathrm{C} \\ & \simeq 165.3^{\circ} \mathrm{C} \end{aligned} $

Asked in: AP EAMCET 2022 (07 Jul Shift 2)

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