A gas absorbs 18 J of heat and work done on the gas is 12 J, Then the change in internal energy of the gas

A gas absorbs 18 J of heat and work done on the gas is 12 J, Then the change in internal energy of the gas
  1. 24 J
  2. 36 J
  3. 6 J
  4. 30 J

Solution

For the gas, $\mathrm{Q}=18 \mathrm{~J}, \mathrm{~W}=-12 \mathrm{~J}$ $\therefore \quad$ Change in internal energy, $\Delta \mathrm{U}=\Delta \mathrm{Q}-\mathrm{W}=18-(-12)=30 \mathrm{~J}$

Asked in: AP EAMCET 2024 (23 May Shift 1)

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